Objective
At the end of this lesson, students should be able to:
When multiplying together expressions in brackets, it is necessary to multiply all terms in one bracket by all the terms in the other bracket.
The total area is (a +b) × (c +d)
= (a + b) (c + d)
It is made up of 4 smaller rectangles with areas ac, ad, bc and bd
So (a + b) (c + d) = ac + ad + bc + bd
OR
All terms in one bracket must be multiplied by each term in the other bracket.
1st (B1) × 1st (B2) = x2
1st (B1) × 2nd (B2) = 4x
2nd (B1) × 1st (B2) = 2x
2nd (B1) × 2nd (B2) = 8
Example 3
Expand and simplify (3x – 3y)2
Solution
The bracket is squared, so we have to write out the bracket twice and multiply each term.
(3x – 3y)2 = (3x – 3y)(3x – 3y)
3x(3x) – 3x(3y) – 3y(3x) – 3y(-3y)
9x2 – 9xy – 9xy + 9y2
9x2 – 18xy + 9y2
Example 4
Simplify (x + 2)(x + 3)
Solution
We multiply x by (x + 3) and 2 by (x + 3)
(x + 2)(x + 3)=
=
= x2 + 3x + 2x + 6
= x2 + 5x + 6
Example 5
Simplify (x + 4)(x + 3) – x2
Solution
(x + 4)(x + 3) – x2 = x(x + 3) + 4(x + 3) – x2
= x x + x 3 + 4 x + 4 3 – x²
= x2 + 3x + 4x + 12- x2
= (x2 – x2)+ (3x + 4x) + 12
= 7x + 12
Example 6
Simplify (y – 2)(2x + 5)
Solution
(y – 2)(2x + 5) = y(2x + 5)- 2(2x + 5)
= 2xy + 5y – 4x -10.